一个小程序

用途：

程序执行的太快，可能相邻2s的日志会交错打印，如果看每秒处理的请求数就不太方便，可以通过如下脚本来解决

脚本：

<?php
/*
 * command: tail -f access_log|awk '{print $5}' |php a.php
 * time format: [03/May/2013:16:51:30
 */

$old = 0;
$mid = 0;
while(!feof(STDIN)) {
        $line = str_replace("[", "", trim(fgets(STDIN)));
        list($day, $month, $year) = explode("/", $line);
        list($year, $h, $i, $s) = explode(":", $year);
        $time = strtotime("$year-$month-$day $h:$i:$s");
        if ($old == 0) {
                $old = $time;
        }
        if ($time - $old > 1) {
                echo date("Y-m-d H:i:s", $old),"\t", $arr[$old], "\n";
                unset($arr[$old]);
                $old = $mid;
        }
        if ($time - $old == 1) {
                $mid = $time;
        }
        $arr[$time]++;
}

<?php

* command: tail -f access_log|awk '{print $5}' |php a.php

* time format: [03/May/2013:16:51:30

$old = 0;

$mid = 0;

while(!feof(STDIN)) {

$line = str_replace("[", "", trim(fgets(STDIN)));

list($day, $month, $year) = explode("/", $line);

list($year, $h, $i, $s) = explode(":", $year);

$time = strtotime("$year-$month-$day $h:$i:$s");

if ($old == 0) {

$old = $time;

}

if ($time - $old > 1) {

echo date("Y-m-d H:i:s", $old),"\t", $arr[$old], "\n";

unset($arr[$old]);

$old = $mid;

}

if ($time - $old == 1) {

$mid = $time;

}

$arr[$time]++;

}

用途：

脚本：

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