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PHP Add comments

3月 102016

如下：

a.php

<?php
namespace A;
use B\Group;
include("b.php");

new Group();

<?php

namespace A;

use B\Group;

include("b.php");

new Group();

b.php

<?php
namespace A;
class Group{
        function __construct(){
                echo "Group in A";
        }
}

namespace B;

class Group{
        function __construct(){
                echo "Group in B";
        }
}

<?php

namespace A;

class Group{

function __construct(){

echo "Group in A";

}

namespace B;

class Group{

function __construct(){

echo "Group in B";

}

php a.php

如果 a.php 中

use B\Group;

1	use B\Group;

则输出的是 Group in B;

否则：输出Group in A;

至少不会冲突

原文链接：https://phpor.net/blog/post/3321

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